Description

Petr wants to make a calendar for current month. For this purpose he draws a table in which columns correspond to weeks (a week is seven consequent days from Monday to Sunday), rows correspond to weekdays, and cells contain dates. For example, a calendar for January 2017 should look like on the picture:

Petr wants to know how many columns his table should have given the month and the weekday of the first date of that month? Assume that the year is non-leap.

Input

The only line contain two integers m and d (1 ≤ m ≤ 12, 1 ≤ d ≤ 7) — the number of month (January is the first month, December is the twelfth) and the weekday of the first date of this month (1 is Monday, 7 is Sunday).

Output

Print single integer: the number of columns the table should have.

Examples

input
1 7
output
6
input
1 1
output
5
input
11 6
output
5

Note

The first example corresponds to the January 2017 shown on the picture in the statements.

In the second example 1-st January is Monday, so the whole month fits into 5 columns.

In the third example 1-st November is Saturday and 5 columns is enough.

Key

写过的最短的题哈哈哈，贴上来以表纪念。其中用到了老司机教我的除法向上取整的方法。

Code

#include<iostream>
int m, d;
const int D[] = { 0,31,28,31,30,31,30,31,31,30,31,30,31 };
int main()
{
	std::cin >> m >> d;
	std::cout << (D[m] + (d - 1) - 1) / 7 + 1;
}

XieNaoban's Blog

Codeforces Round 393(Div. 2) - A. Petr and a calendar